ErdosProblems · research open · AMS 5

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Erdős Problem 1020

Conjecture 1020 · Erdős

Let f(n;r,k)f(n;r,k) be the maximal number of edges in an rr-uniform hypergraph which contains no set of kk many independent edges.

For all r≥3r\geq 3, f(n;r,k)=max⁡((rk−1r),(nr)−(n−k+1r)).f(n;r,k)=\max\left(\binom{rk-1}{r}, \binom{n}{r}-\binom{n-k+1}{r}\right).

Note: the source states the formula with no range on n or k, but some restriction is needed: e.g. for r = 3, k = 2, n = 4 no two disjoint triples fit in 4 vertices, so the left-hand side is 4.choose 3 = 4 while the right-hand side is 5.choose 3 = 10. We require k ≥ 1 and n ≥ r*k - 1: this is the smallest n accommodating the construction counted by the first term (all r-subsets of a fixed (r*k - 1)-set), and at n = r*k - 1 the equality holds trivially, since the complete r-uniform hypergraph has no k-matching. The source's commentary likewise calls the case n < k*r trivial.

Formal statement · Lean 4.lean
theorem erdos_1020 (r : ℕ) (hr : 3 ≤ r) (n k : ℕ) (hk : 0 < k)
    (hrk : r * k - 1 ≤ n) :
    f n r k = max ((r * k - 1).choose r)
      (n.choose r - (n - k + 1).choose r) := by
  sorry

Proof. sorry

Nobody has tried yet.

Reference ↗ · Lean source ↗